🏆【2018教育部教學實踐研究計畫】(4K) 2014成大:Solve x’ = 2x + y + exp(‒t), y’ = x + 2y, x(0) = y(0) = 1

🏆【教學影片】(4K) 2014成大:Solve x’ = 2x + y + exp(‒t), y’ = x + 2y, x(0) = y(0) = 1

🏆【解題講義】https://s.chu.edu.tw/R.aspx?rd=KXydeE