🏆【2018教育部教學實踐研究計畫】(4K) 2014中興:Solve L{f(t)}, f(t) = 2t ‒ sint for 0 ≦ t<π, f(t) = 0 for t ≧ π

🏆【教學影片】(4K) 2014中興:Solve L{f(t)}, f(t) = 2t ‒ sint for 0 ≦ t<π, f(t) = 0 for t ≧ π

🏆【解題講義】https://s.chu.edu.tw/R.aspx?rd=H8DQsT